On May 16, 2014 1:58 PM, "Alex Efros" <[email protected]> wrote:
>
> Hi!
>
> On Fri, May 16, 2014 at 12:53:17PM +0400, Nikolay Pavlov wrote:
> > On May 16, 2014 12:29 PM, "Alex Efros" <[email protected]> wrote:
> > > > > fun s:Foo()
> > > > > endfun
> > > > > let g:Foo = function('s:Foo')
> > This change has nothing to do with the change that made
function('s:...')
> > work outside of the plugin which defined this funcref. It was a bug that
> > got fixed.
>
> User reported it on Ubuntu 12.04 LTS with Vim 7.3.429-2ubuntu2.1, I see it
> on 7.3.762 - so, this bug exists in so many vim versions?
It existed since the time when function() was introduced. Until I wrote a
patch that expanded s: when defining funcrefs nobody seemed to be bothered
with the fact that you cannot call s: funcrefs outside of the plugin which
defined them.
>
> > To workaround it on old vims you should use manually replace s: with
> > <SNR>N_ when defining funcrefs. AFAIR :h <SID> shows some ways to get N.
>
> You mean I should add
>
> function s:SID()
> return matchstr(expand('<sfile>'), '\zs<SNR>\d\+_\zeSID$')
> endfunction
>
> into each file of my plugin (it uses sort of sub-plugins in separate
> files, so there a lot of them), and then replace in each file each
>
> let g:Foo = function('s:Foo')
>
> with
>
> let g:Foo = function(s:SID().'Foo')
>
> And this is only way to keep compatibility with these vim versions?
I would recommend switching to anonymous functions if you do not like this
variant. There are no other ways I know about.
Anonymous functions:
let s:F = {}
function s:F.foo()
endfunction
let g:Foo = s:F.foo
. But this has one problem: anonymous functions cannot be called without a
dictionary. So to call g:Foo you will either need to always use 3-argument
form of call() or define g:FooDict with 'foo' key and call using
g:FooDict.foo().
>
> --
> WBR, Alex.
>
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