On Sunday, November 1, 2015 at 12:16:43 AM UTC+9, Ken Takata wrote:
> Hi mattn,
> 
> 
> 2015/11/1 Sun 0:01:27 UTC+9 mattn wrote:
> > > Thanks.  Is there any corner case where we would need a few more bytes
> > > than MAXPATHL?
> > 
> > In utf-8, max bytes of letter should be 4. So MAXPATHL * 4.
> 
> No, I don't think so.
> On Windows, MAX_PATH (260) characters in WCHAR is the maximum path length.
> So the length is MAX_PATH * 3 bytes in UTF-8.
> In my understanding, MAXPATHL (1024) is the maximum characters of the path
> in char_u which is encoded with 'encoding'.
> So MAXPATHL is enough.
> 
> Regards,
> Ken Takata

Ah, right.

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