ivan budiselic wrote:
>>> So, for the line:
>>>
>>> 1234 a a "a" a
>>>
>>> I'd like to get:
>>>
>>> 1234 b b "a" b
>>>
>>> The question is, is this possible and how.
>>>
>>> What I've tried is
>>> let line = substitute(line, '\([^\"]\{-}\)a', "\\1b", "g")
>>
>> ...because \{-} matches also 0 times; what you wanted is \{-1,}:
>>
>> let line = substitute('123 a "a" a', '\([^"]\{-1,}\)a', '\1b', 'g')
>>
>
> Ok, this worked pretty well, except that it doesn't work for cases when
> there's an 'a' at the start of the line (which I might be able to fix), and
Allow matching 'start-of-line' (^) in front of 'a', too; see below.
> the other problem which I wasn't specific enough about, and that is that I'd
> like the change to happen to 'a's outside of strings, so for example
> "xxxaxxx" shouldn't match. I guess this changes things quite a bit, sorry
> for not being clear enough.
So, would you like further help? If yes, could you provide an example for what
you want to achieve?
s/\(^\|\s\)\zsa\ze\s\?/b/
works for
a 123 a a "xxxxaxxx" a
==>
b 123 b b "xxxxaxxx" b
--
Andreas.
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