> First, how do I replace a line that begins with a
> pattern with a line with only \n ? I tried
>
> :1,$ s/^pattern/\n/g
>
> but it didn't work.
For some reason, Vim's newline replacement is \r instead of \n
which I wish I could explain better than "well, that's the way it
is". So you can do
:%s/^pattern/\r
(the /g flag is unneeded because you're anchored to the beginning
of the line, of which there's only one). If you want to replace
the whole line (in the event you have a line that looks like
break; // stuff here
), then your pattern has to consume the whole line:
:%s/^pattern.*/\r
> A similar question is about replacing
>
> break;
>
> with
> {
> break;
> }
If you don't need to keep the level of indent, it's pretty easy:
:%s/break;/{\r\t&\r}/g
(assuming you want a "\t"ab instead of spaces...adjust
accordingly if you want spaces instead). If, however, you want
to keep the indent, it gets a little dirtier:
:%s/\(\s*\)break;/\1{\r\1\tbreak;\r\1}/g
which captures the whitespace before the "break;" with "\(\s*\)"
and then uses it to put back in before the "{", the "\tbreak;"
and the "}".
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