> On Fri, Sep 25, 2009 at 11:59 AM, Andy Wokula <[email protected]> wrote:
>
>> > Jeremy Conlin schrieb:
>>> > > That didn't quite work and it's my fault for not giving better
>>> > > examples.
>>> > > Here are two lines:
>>> > >
>>> > > The genealogies & & 1:2--17 & & 3:23--38 & & \\
>>> > > Elisabeth's seclusion & Judaea: Bethlehem & & & 1:24--25 & & \\
>>> > >
>>> > > I want my regular expression to find the first line and not the second
>>> > > because there is non-whitespace between the second and third ampersand.
>>> > > What I'm trying to do is replace "1:2--17" with "\index{1:2--17}"
>>> > >
>>> > > Is that example more clear?
>>> > >
>>> > > Thanks,
>>> > > Jeremy
>> >
>> > this way?
>> > pattern:
>> > /^\%([^&]*&\)\{2}\s*[0-9:-]\+
>> >
>> > substitute command (with \zs added in the pattern):
>> >
>> > :%s/^\%([^&]*&\)\{2}\s*\zs[0-9:-]\+/\\index{&}/
>> >
>> > will not work if "&" somehow occurs escaped as part of an entry.
>
> Yes this works. Thanks! Now do you mind help me understand what everything
> means, I don't quite understand everything you did?
>
> Jeremy
Regexp patterns are described here:
:h pattern
The pattern:
/^\%([^&]*&\)\{2}\s*[0-9:-]\+
Literal chars: &
Special chars
^
\%( ... \)
[ ... ]
[^ ... ]
*
\{ ... }
\s
\+
Find the help topic e.g.
:h /^
:h /\%(
etc.
The replacement string: \\index{&}
:h sub-replace-special
Literal chars: i n d e x { }
Special chars:
\\
&
--
Andy
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