Hi Bee!
On Mi, 30 Sep 2009, Bee wrote:
> How to use something like repeat() to create a string like:
>
> '" '.(((start at 3 increment by 1) mod 10) for count of 62)
>
> resulting in:
>
> " 34567890123456789012345678901234567890123456789012345678901234
fu! Repeat(start, mod, count)
let i=1
let s=[]
call add(s,a:start)
while i < a:count
call add(s,(s[i-1]+1)%a:mod)
let i+=1
endw
return join(s, '')
endfu
:echo Repeat(3,10,62)
34567890123456789012345678901234567890123456789012345678901234
regards,
Christian
--
"The Mac OS X kernel should never panic because, when it does, it
seriously inconveniences the user."
--http://developer.apple.com/technotes/tn2004/tn2118.html
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