Christian Brabandt schrieb:
> On Tue, October 20, 2009 8:55 am, Jeri Raye wrote:
>> I have a long list with lines that start with a number in random order
>> followed by tekst.
>> Something like this:
>>
>> 109 AAA
>> 23 blabla
>> 1 xyzxyz
>> 45 BBB
>>
>> What I want is that all number get one or more 0 needed then the
>> largest (in character size) number
>> So in the list above the 'largest' number is 3 characters.
>>
>> 109 AAA
>> 023 blabla
>> 001 xyzxyz
>> 045 BBB
>>
>> But if there was a bigger number for example 12345 in the list (not
>> shown now in this example) ) the above list should become
>> 00109 AAA
>> 00023 blabla
>> 00001 xyzxyz
>> 00045 BBB
>>
>> How to do that?
>
> Well, you need to calculate the max length of the first item. I am not
> sure, you can do this on the fly, so I defined this function:
>
> fu! MaxLen()
> return strlen(max(map(getline(1,"$"), 'matchstr(v:val, "^\\d\\+")')))
> endfu
>
> Using this function, I could then run a substitute command like this:
> :%s/^\d\+/\=printf("%0".MaxLen()."d",submatch(0))/
>
> Which worked for me.
>
> PS: Anybody knows why map(getline(1,"$"), 'matchstr(v:val, "^\\d\\+")')
> worked, but not map(getline(1,"$"), "matchstr(v:val, '^\d\+')"), which
> would have the benefit of not having to double escape the regular
> expression, thus looking clearer?
>
> regards,
> Christian
Alternative for MaxLen():
func! LongestNumLen()
let len = 1
1
while search('^\d\{'.len.'}', 'cW')
let len += 1
endwhile
return len-1
endfunc
which will also put the cursor on the longest match.
--
Andy
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