epanda wrote:
>
> On 24 déc, 15:14, Tim Chase <[email protected]> wrote:
>>> Goal : multiply some parts of lines which contain factors
>>> foo(2)bar(9)
>>> Should become
>>> foo1bar1
>>> foo1bar2
>> ...
>>> foo1bar9
>>> foo2bar1
>>> foo2bar2
>> ...
>>> foo2bar9
For something close, you can use the following python code that is
pretty speedy and should handle arbitrary counts of repeats, and pad in
the optionally missing bits with "1"
###########################################
import re
r = re.compile(r'\((\d+)\)')
def printall(leader, bits):
if bits and bits[0].strip():
text = bits[0]
try:
times = int(bits[1])
except:
times = 1
for i in range(times):
printall(
'%s%s%i' % (leader, text, i+1),
bits[2:]
)
else:
print leader
for line in file('epanda.txt'):
line = line.rstrip('\n')
if r.search(line):
printall('', r.split(line))
else:
print line
###########################################
You can tweak the behavior for those lines that have no count so they
behave as you want.
-tim
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