numbering lines in groups
Thanks to this list I have "grouped" line numbering working.
It is not a normal sequential numbering, but in groups of n lines.
Example n=2
( 1_0_)
( 1_1_)
( 1_2_)
( 2_0_)
( 2_1_)
( 2_2_)
( 3_0_)
( 3_1_)
( 3_2_)
( 4_0_)
( 4_1_)
( 4_2_)
I had a problem when using n=15 as follows, it worked like n=2. I
discovered that only the first "digit" was being compared @l<@n, seems
to be a string compare.
--THIS FAILS--
vmap <F5> :<C-U>let @n=15 <BAR> let @b=1 <BAR> let @l=0 <BAR>
\ '<,'>s/^/\=printf("( %4d_%X_)",
\ @b + setreg('b', @l<@n ? @b : @b+1 ),
\ @l + setreg('l', @l<@n ? @l+1 : 0 ))<cr>
endif
So I tried using a variable instead of a register and it worked.
--THIS WORKS--
vmap <F5> :<C-U>let n=15 <BAR> let @b=1 <BAR> let @l=0 <BAR>
\ '<,'>s/^/\=printf("( %4d_%X_)",
\ @b + setreg('b', @l<n ? @b : @b+1 ),
\ @l + setreg('l', @l<n ? @l+1 : 0 ))<cr>
endif
Then searching the excellent vim help found str2nr(), said I, ok!
--THIS WORKS--
vmap <F5> :<C-U>let @n=15 <BAR> let @b=1 <BAR> let @l=0 <BAR>
\ '<,'>s/^/\=printf("( %4d_%X_)",
\ @b + setreg('b', @l<str2nr(@n) ? @b : @b+1 ),
\ @l + setreg('l', @l<str2nr(@n) ? @l+1 : 0 ))<cr>
endif
QUESTION: Why does @l<n work and @l<@n fail? Where do I find help?
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