> > Hum, I know but nothing is smarter and faster before implementing a
> > for loop?
>
> If all the elements of list1 are unique, you could use map() and index().
>
> map(list1, 'v:val."*".list2[index(list1,v:val)]')
>


Ok this is perfect. It works like excel and faster I think...ust for
adding operations for the moment.

Thank you a lot Israel.

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