On Thu, January 13, 2011 10:50 am, rameo wrote:
> Is it possible to round numbers within vim?
>
> I use this command to find numbers in my text with decimals:
>
> :%s/\(\d\{1,}\)\(\,\)\(\d\{1,}\)/ xxx /g
>
> I would like to replace "xxx" with
>
> if decimal >= ,5 --> round up and remove decimals
> p.e. 4,5 --> 5
>
> if decimal < ,5 --> round down and remove decimals.
> p.e. 4,4 --> 4
>
> but I don't know how to insert this in above substitute command.
> Can anyone help me?
This can be done like this:
:%s/.../\=float2nr(round(str2float(substitute(submatch(1), ',', '.', ''))))
this looks a little bit ugly, but you need first to replace your , by a
dot so it can be successfully converted to a float, than round the float
and convert it back to an integer.
However, I think, your search regex can be simplified a bit to something
like this:
\d\+,\d\+
and you don't even need to group this expression, since you can use
submatch(0) to replace the whole matching pattern.
So put it all together like this:
:%s/\d\+,\d\+/\=float2nr(round(str2float(substitute(submatch(1), ',', '.',
''))))/g
(this is one line, in case the mail get's mangled)
regards,
Christian
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