googler wrote:
> I have one question related to the solution given there.
> :let i=1 | g/foo/s//\="blah_".i/ | let i=i+1
That is two commands:
:let i=1
:g/foo/s//\="blah_".i/ | let i=i+1
and the second of these is:
:g/foo/
:s//\="blah_".i/
:let i=i+1
:g works by flagging each line containing the search pattern
('foo'). It then executes the Ex command that follows after the
':g/foo/' for each flagged line.
The s//.../ changes the first occurrence of 'foo' on the line,
then i is incremented. That is repeated for each flagged line.
John
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