Reply to message «Re: vim function not first-class variable? how to create an alias for vim function ?», sent 12:41:23 05 July 2011, Tuesday by Marc Weber:
> Note: F must be upper case, cause functions can only be assigned to
> upper case vars.
F can be inside dictionary, in this case it does not matter. It also avoids
E705
error: you can't do
let Foobar=function('Foobar')
, but can
let d={}
let d.Foobar=function('Foobar')
> That implements a function reference by using a special key in a dict.
> This way you can also add args to the function ref:
>
> let f = funcref#Function('FooBar',{'args': [ 1, 2] })
>
>
> call funcref#Call(f, [2,3])
>
> will call FooBar(1,2, 2,3)
>
> It also supports kind of eval functions definitions:
>
> let f = funcref#Function("return ARGS[0]")
>
> last but not least obj like functions:
>
> let X = {}
>
> fun X.A(a,b)
> echo a:a
> echo a:b
> endf
>
> call X.A(2,3)
> let C = X.A
> call call(C,[], X) " or the like
1. What is it for?
2. Why not f.call(args) instead of funcref#Call(f, [args])?
Original message:
> Excerpts from pansz's message of Tue Jul 05 10:24:05 +0200 2011:
> > I want to do some coding like this:
> let F = function('Foobar')
>
> call call(F, [arg1, arg2], { optional self dict })
>
> Note: F must be upper case, cause functions can only be assigned to
> upper case vars.
>
> Also see vim-addon-mw-utils (on my github page).
>
> That implements a function reference by using a special key in a dict.
> This way you can also add args to the function ref:
>
> let f = funcref#Function('FooBar',{'args': [ 1, 2] })
>
>
> call funcref#Call(f, [2,3])
>
> will call FooBar(1,2, 2,3)
>
> It also supports kind of eval functions definitions:
>
> let f = funcref#Function("return ARGS[0]")
>
> last but not least obj like functions:
>
> let X = {}
>
> fun X.A(a,b)
> echo a:a
> echo a:b
> endf
>
> call X.A(2,3)
> let C = X.A
> call call(C,[], X) " or the like
>
> Marc Weber
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