On 20/07/11 11:32, Tony Mechelynck wrote:
On 20/07/11 10:21, Chen San wrote:
i have saw some usages in such a form:
let i=1 | g/foo/s//\="blah_".i/ | let i=i+1
then my question is, what if i wanna substitute something with a list,
such as ['one','two','three']
i have try the next script:
let i=0
let alist=['one','two','three']
for n in alist
g/foo/s//\=n/
endfor
let i=i+1
but all the 'foo' there would be replaced with 'one', not the 'two' or
'three'.
anyone have any ideas?
thanks.
the problem with
for n in alist
g/foo/s//\=n/
endfor
is that you'll set n to 1, scan the whole file replacing foo by the
value of n (which is 1) then scan the whole file again with n=2, not
find any foo, etc.
Your first idea is in a better direction: I think that
:let i=1 | g/foo/s//\=i/g|let i+=1
or
:let i=1 | exe 'g/foo/s//\=i/g|let i+=1' | unlet i
oops! Forgot that you wanted the i-th item in the list
:let i=0 | g/foo/s//\=alist[i]/g|let i+=1
would work, provided that there are no more occurrences of foo than the
length of the list. (the :let i+=1 is regarded here as part of the
argument of the :g command, so it is executed immediately after the
substitute on every matching line.)
The /g switch assumes that you want to replace every occurrence of
"foo", even several per line and even in the middle of a word. You can
of course restrict that by means of the following zero-length pattern
items:
\< start of word
\> end of word
^ start of line
$ end of line
Best regards,
Tony.
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