Hi AK, On 09/11/2011 12:26 AM, AK wrote: > On 09/10/2011 05:53 PM, Gelonida N wrote: >> Hi, >> >> >> I have a small question. >> >> for some text_file I wanted to use foldmethod=ident >> >> >> I have following >> buffer ( no tabs / only blanks) >> >> >> 0000000 >> 0000000 >> 0000000 >> 11111111111111 >> 111111111111 >> 1111111 >> 22222222222222222 >> 22222222222222222 >> 22222222222222222 >> 22222222222222222 >> 22222222222222222 >> >> >> >> All the lines containing '2' can be folded and unfolded >> >> however vim does not fold the first level so the lines with '1' >> characters are not being folded.
> > It has to be 4, not 5 spaces, I think then it will indent. -ak Well this was not the problem, as my original code had four spaces. It seems I accidentally overwrite my shiftwidth setting in my vimrc. as soon as I added set sw=4 it was working again (the default sw is 8 and thus only the second level of indentation was folded) In fact if sw=4, then indents of 4,5,6,7 are treated as the same fold level Thanks a lot of putting me on the right track. I didn't even think, that the shiftwidth is related to the folding. -- You received this message from the "vim_use" maillist. Do not top-post! Type your reply below the text you are replying to. For more information, visit http://www.vim.org/maillist.php
