On Sep 11, 9:58 am, ZyX <[email protected]> wrote:
> If you use eval('"'.escape(maparg(...), '\<"').'"') instead of substitute() it
> will be more reliable and you still won't have to use :imap.
Great. I was wondering whether there is a way to go from things
like '<NL>' to the actual character represented. But still it
would be nice if there was a function which gave you the
abbreviation exactly as the string which will be inserted. With
eval('"'.escape(maparg(...), '\<"').'"') I'm worried that
perhaps some special cases won't work correctly although I don't
have a specific example in mind.
> But you may want to
> replace `d$' with something other: it won't work if you press <C-y> not at the
> end of line. Maybe something like this:
>
> function s:ExpAbbr()
> let line=getline('.')[:col('.')-1]
> let lhs=matchstr(line, '\v\S+$')
> let rhs=maparg(lhs, 'i', 1)
> if empty(rhs)
> return ''
> endif
> " Assuming that {lhs} contains only ASCII characters. If you want,
> " replace len(...) with strchars(...) (assuming there are no composing
> " characters) or len(split(lhs, '\v.@=')).
Will len(split(lhs, '\v.@=')) always return the same result as
len(split(lhs, '\zs')) or strlen(substitute(lhs, ".", "x", "g"))
both of which appear in the documentation ?
> let r=repeat("\ecl", len(lhs))
> " Assuming that all abbreviations are noremappable
> let r.=eval('"'.escape(rhs, '\<"').'"')
> " let r.="Additional actions"
> return r
> endfunction
>
> inoremap <expr> <C-y> <SID>ExpAbbr()
Thanks for this.
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