On 07/11/11 06:37, Bee wrote:
On Nov 6, 9:14 pm, Christian Brabandt<[email protected]> wrote:
Hi Tim!
On So, 06 Nov 2011, Tim Chase wrote:
On 11/06/11 19:04, Quincy Bowers wrote:
Ah, I wonder if abbreviations can only be defined if they
don't cross keyword boundaries... And if that is the case is
that intended?
That's why I was confused that
:iab @a @author Author Name
worked, but
:iab @author @author Author Name
errored out.
That is explained at :h abbreviation.
,----
| There are three types of abbreviations:
|
| full-id The "full-id" type consists entirely of keyword
| characters (letters and characters from 'iskeyword'
| option). This is the most common abbreviation.
|
| Examples: "foo", "g3", "-1"
|
| end-id The "end-id" type ends in a keyword character, but all
| the other characters are not keyword characters.
|
| Examples: "#i", "..f", "$/7"
|
| non-id The "non-id" type ends in a non-keyword character, the
| other characters may be of any type, excluding space
| and tab. {this type is not supported by Vi}
|
| Examples: "def#", "4/7$"
`----
So while @a is of type end-id @author isn't.
regards,
Christian
:set isk?
returns:
iskeyword=@,48-57,_,192-255
That means @ is a keyword character,
it also means _ is a keyword character,
and both the following SHOULD be full-id.
This fails:
:iab @author @author Author Name
But this seems to be ok:
:iab _author @author Author Name
-Bill
In the value of 'iskeyword' (whose explanation resends to 'isfname'), @
doesn't mean @, it means A-Za-z (plus maybe á, é, etc.). To make the @
character a keyword character, use @-@
Best regards,
Tony.
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