On 11/22/11 07:16, Graham Lawrence wrote:
Then they are quite different, I was thinking /@" in script would be
the equivalent of /^R" at the command line.
You can do the following in a script which, while 2 steps, I find
equally clear as Tony's use of search()
let @/=@"
/
The first line assigns the contents of the scratch register to
the search register and the second line searches for it (somewhat
the equiv. of hitting "n" in normal mode) since there's no regexp
after it. Either method works, and one or the other may have
subtle advantages over the other (clarity of search-direction,
verbosity, etc)
As a side-note, depending on your line's contents, you may have
to wrap the value of @" in a call to escape(), as in
let @/=escape(@/, '.\[*~')
call search(escape(@/, '.\[*~'))
(untested, though the only gotcha would be my accidental omission
of some characters to be escaped)
-tim
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