On Sun, 26 Aug 2012, Andy Wokula wrote:
Am 20.08.2012 22:58, schrieb cybrown:
I'm a relatively new VIM user, and I've been playing vimgolf
(www.vimgolf.com) to learn new skills. This challenge has a bizarre
solution that I don't understand:
http://www.vimgolf.com/challenges/4d1db1b8de2f897c2a00014a
Here's the shortest solution posted:
a.<BS><CR><Esc>[email protected]
First off, I didn't realize @. was a valid macro combination. So, my
questions:
1) Is @. any different than .? Why would I want to use one instead of the
other?
2) What's going on with this solution? Why does it work but:
a<CR><Esc>[email protected]
doesn't work? What's so special about inserting the dot specifically?
All in all, it's a tricky one; in order to congrat the author I'll
give a lengthy explanation :-)
Pretty good explanation. Two nits:
He implicitly records into the `.' register by typing `.' in Insert mode
("recording" is later stopped with `<Esc>');
He implicitly records into the ". register because he's inserting text
with `a'. The ". register "Contains the last inserted text" according
to
:help quote.
You can record into ". via i, I, a, A, o, O, and <Insert> (possibly
others -- those are the ones I could find quickly).
the dot is not wanted for the line break, so he also hits `<BS>'.
`@.' is executed in Normal mode where the sequence `.<BS><CR>' gets a
different meaning.
For this special case, `<BS><CR>' is a no-op, so `24@.' executes `.' 24 times
in a row, with the intended result.
`<BS><CR>' is <BS> (equivalent to `h', except that 'whichwrap' contains
'b,s' by default, so <BS> wraps over line breaks) followed by <CR>
(equivalent to `+'). So <BS><CR> moves up a line (because we're on the
first character of the line and it wraps) and down a line. So it's only
a "no-op" because it's not performed on the first line of the file
(where it would move down by one).
--
Best,
Ben
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