On Tuesday, September 18, 2012 10:02:32 AM UTC-5, Ben Fritz wrote: > On Monday, September 17, 2012 12:07:58 PM UTC-5, Martin Jiricka wrote: > > > Hello! > > > > > > > > > > > > First of all, thank you for your reply! > > > > > > > > > > > > > I think you wanted one of these: > > > > > > > \v(123)@<=abc > > > > > > > > > > > > Yes, this is what I wanted. > > > > > > > > > > > > > Additionally, if this WERE working as you expect, your pattern would > > > NEVER > > > > > > > match. You are saying, > > > > > > > "match abc where 123 also matches in the same position" > > > > > > > which cannot possibly succeed, because 123 does not match where abc > > > matches. > > > > > > > > > > > > I don't get this. Of course I didn't want to match 'abc' on '123'. (That's > > the purpose of regexes, match pattern where the pattern match, I would > > say...?) I posted simplified example, originally I wanted to match last > > word before the parenthesis, which is a function name. The '@<=' works fine > > for this. > > > > > > > > > > Yes, and @<= is what you wanted. You used @=, which is a zero-width > look-ahead, not a look-behind. > > > > E.g. /\(abc\)\@=\a\+ will match the whole string "abcdefghij"; it says "find > a string of alphabetic characters starting with 'abc'". /\(abc\)\@<=\a\+ will > match the "defghij" in "abcdefghij" only; it says, "find a string of > alphabetic characters preceded by 'abc'".
Incidentally, I cannot recall ever having a use for \@=. As the help says, it does the same thing as \&. -- You received this message from the "vim_use" maillist. Do not top-post! Type your reply below the text you are replying to. For more information, visit http://www.vim.org/maillist.php
