Hi Ben!
On Di, 09 Okt 2012, Ben Fritz wrote:
> On Tuesday, October 9, 2012 8:10:29 AM UTC-5, Christian Brabandt
> wrote:
> >
> > You need to loop over each line and get the diff_hlID() for that
> > position.
> >
> > Each line, where diff_hlID() returns zero you need to delete.
> >
> >
> >
> > Of course, you can do it in one step ;)
> >
> >
> >
> > exe ':g/'. join(map(filter(range(1,line('$')), '!diff_hlID(v:val,
> > 0)'), '
> >
> > ''\%''.v:val."l"'), '\|'). '/d'
> >
> >
> >
> > But, this works only once, you can't do this for all buffers at the
> >
> > same time, since after you changed the first buffer the syntax
> > highlighting
> >
> > for the other will be completely different and there will be no more
> >
> > items being in common at the following buffers.
> >
>
> But, you could next undo the (single) change in the first buffer,
> repeat the process on the second buffer, then redo the change in the
> first buffer.
Even better, store the result for each window and execute it afterwards:
:let delete={}
:windo if &diff |:let delete[bufnr('')]=
join(map(filter(range(1,line('$')), '!diff_hlID(v:val, 0)'),
'''\%''.v:val."l"'), '\|')|endif
:windo if &diff | exe ":g/". delete[bufnr('')]."/d"|endif
:unlet delete
(each line starting with ':' is a single line, no linewraps)
regards,
Christian
--
Unter Rationalisierung verstehen die meisten Postminister, daß man
die Gebühren laufend erhöht und die Zustellung ständig verschlechtert.
-- Cyril Northcote Parkinson
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