Ben,
On 2012-11-21 07:20, Ben Fritz wrote:
On Tuesday, November 20, 2012 1:48:55 PM UTC-6, Philip Rhoades wrote:
On Nov 20, 2012; 8:01am, Ben Fritz wrote:
> On Monday, November 19, 2012 2:31:49 PM UTC-6, Philip Rhoades
wrote:
>> I have been playing around with folding options in .vimrc but
can't
>>
>> work out how to do what I want which is:
>>
>> - Fold all blocks between the first line of the block and the
"end"
>>
>> line but ONLY only for those blocks whose first line starts at
>> column 1.
>>
>> Is this possible?
>>
>
> What do you mean by "block"? How do you know where it starts and
> ends? This should be fairly easy to do with a foldexpr.
Sorry, silly of me - I should have said when editing Ruby blocks eg:
if (..)
.
.
end
or
tst = proc{ tarr
.
.
}
First, it looks like this will fold more than you want, but just in
case it
is acceptable to you, have you tried the Ruby syntax folding?
Yes, I did look at that and yes it was too much.
See :help ruby.vim for the options on Ruby syntax. Near the end are
the
folding options ruby_fold and ruby_no_comment_fold.
If all you want is the specific blocks you mention, and if you're not
too
worried about being precisely correct, you could make a foldexpr
which
depends on not only the beginning of the match but also the end being
in the
first column. Something like:
fun! MyFoldBlocks()
if getline(v:lnum)=~'\v^(if|(\S&.*\{)|SomeOtherBlockBeginning)'
return ">1"
elseif getline(v:lnum)=~'\v^(end|\}|SomeOtherBlockEnding)'
return "<1"
else
return "="
endif
endfun
setl foldexpr=MyFoldBlocks() fdm=expr
This nearly does what I want but I want the first (and maybe the last
line?) of the block visible eg:
if ..)
folded
end
since the actual blocks can get quite large and I just want to see the
overall logic. I guess that means doing something with lnum?
Thanks!
Phil.
--
Philip Rhoades
GPO Box 3411
Sydney NSW 2001
Australia
E-mail: [email protected]
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