Hi Marc!
On Mo, 18 Feb 2013, Marc Weber wrote:
> > No, it is because "\n" is evaluated to a true line feed, so "[^\n]"
> > matches anything but ASCII NUL and ASCII 10, while '[^\n]' matches
> > anything but ASCII NUL (which is used internally by Vim to distinguish
> > lines from each other (e.g. a line seperator), so that a . matches
> > anyhing in the buffer but the line seperator)
>
> Christian: Once and for all - I don't want anybody to explain me that
> [^\n] behaves in a wired way because '.' should behave the way it does.
>
> I'm *not* talking about internals. I'm talking the user interface you
> and me and new users are faced with every day. So help me think about
> whether there is a way to improve the situation.
>
> So why should anybody write [^\n] if you can use '.'? So why make [^\n]
> behave the same way? Why not make it raise an error such as:
Because [^\n] is perfectly valid?
>
> E99999: For odd reasons you should try "[\n]" instead of '[^\n]' and be
> done. True reason see long reply by Christian on ml ..
>
> Trouble solved within 2 min. No debugging why vim does not behave the
> way you expect. This guard would be trival to implement. if []
> collections are negated and contain \n show the message.
If you don't want that, use :set cpo+=l
> And it would not break backward compatibility. Which is the use case for
> allowing '[^\n]' at all?
It is a perfect valid regular expression. What is the reason to forbid
its use?
Anyway, I just made a patch, that should match your expectations.
regards,
Christian
--
Adam - der erste Entwurf für Eva.
-- Jeanne Moreau
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