Am 18.04.2013 15:27, schrieb David Fishburn:
Vim 7.3.758
I have the following string:
'match /\%(if\|elsif\|unless\|given\|when\|default\)\>/ match /\<\>/
nextgroup=perlElseIfError skip0 skip1 skip2'
I was hoping (using 1 or 2 substitution commands) to find all words less
than or equal to 5 characters in length and remove them.
But, these words have to be within "match /.../" tags.
So, when completed, the string above should read:
'match /\%(\|\|unless\|\|\|default\)\>/ match /\<\>/
nextgroup=perlElseIfError skip0 skip1 skip2'
Notice the skip0, skip1, skip2 are not touched since they are not within
the beginning "match /" and the ending "/" of the match.
My best try was the following:
echo substitute( 'match /\%(if\|elsif\|unless\|given\|when\|default\)\>/
match /\<\>/ nextgroup=perlElseIfError skip0 skip1 skip2', '\<match
/.\{-}\zs\<\w\{1,5}\>\ze.\{-}/ ', '', 'g' )
But it only gets rid of the "if" at the start, and doesn't work on any of
the other matches.
TIA,
David
You could try the pattern
/\%(match \/[^/]*\)\@<=\<\w\{1,5}\>
--
Andy
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