On Sunday, August 11, 2013 2:44:28 PM UTC+12, ping wrote:
> any idea of what I missed here?
With
:g#\(abc\d\+\)\(.*\)\(abc\d\+\)\(.*\)#s//\=Diff(submatch(1),submatch(2))/n
I get all lines reporting a difference, changing the echo to
echo "found a diff!" a:a a:b
shows me why.
Back references are numbered from the left, by their opening \(. Your pattern
is
\(abc\d\+\)\(.*\)\(abc\d\+\)\(.*\)
where you've bracketed the middle bit, so that's returned by submatch(2); you
want to compare matches 1 and 3. Using
:g#\(abc\d\+\)\(.*\)\(abc\d\+\)\(.*\)#s//\=Diff(submatch(1),submatch(3))/n
I get
found a diff! abc123 abc1234
found a diff! abc123 abc1234
5 substitutions on 5 lines
It's an ugly hack, any way. I've just noticed that the matchlist() function
gives access to submatches, a function using that would be cleaner:
func! Diff2(pat)
call setpos('.',[0, 1, 1, 0]) " go to beginning
while search(a:pat, 'W')
let l = matchlist(getline('.'),a:pat)
if len(l) >= 4 && l[1] != l[3]
echo 'found a diff:' l[1] l[3]
endif
endwhile
endfunc
:call Diff2('\(abc\d\+\)\(.*\)\(abc\d\+\)\(.*\)')
Regards, John Little
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