On Mon, Dec 16, 2013 at 12:38:34AM +0400, Nikolay Pavlov wrote:
> Dictionaries are passed by reference. So dictionaries in s:data_n and
> s:candidates... are exactly the same dictionaries and you can just use
>
> function candidate.function_a()
>
> and it will be accesible as both s:candidates[n].function_a and
> s:data_n.function_a.
Ah, he he… great ! Embarrassing for me but great ! :)
> There is no need in generating multiple functions with exactly the same
> body though:
That is very true. But ->
> function is not bound to the dictionary thus you can simply
> generate it once and assign obtained funcref.
No sure what (or how) you mean here. You mean something like the
following ?
<--
function! Mfun() dict
echo self.a_key
endfunction
let Mref = function('Mfun')
let mdict = { 'a_key': "Hello", 'fun': Mref }
-->
Thanks again for your help and best regards,
--
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| $ post_tenebras ↲ | waouh !
| GNU \ / | /
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| $ who ↲ / \ |_-- ~_|
| Alexandre Hoïde | _/| |
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