Am 2014-06-10 11:10, schrieb Ni Va:
On Tuesday, June 10, 2014 10:30:30 AM UTC+2, Christian Brabandt wrote:
Am 2014-06-10 09:40, schrieb Ni Va:
> Hi,
>
>
> I got a file that contains those lines :
>
>
> \s\s\s\s\sFOO
> BAR1
> BAR2
> END_OF_BLOCK
> \s\s\s\s\sFOO2
> BAR1
> BAR2
> END_OF_BLOCK
> \s\s\s\s\sFOO3
> BAR1
> BAR2
> END_OF_BLOCK
>
>
> I would like to indent all sublines of each BLOCK to be like that :
>
> \s\s\s\s\sFOO
> BAR1
> BAR2
> END_OF_BLOCK
> \s\s\s\s\sFOO2
> BAR1
> BAR2
> END_OF_BLOCK
> \s\s\s\s\sFOO3
> BAR1
> BAR2
> END_OF_BLOCK
>
>
>
> My file contains 500000 lines so it has to be done automatically
That should work:
v/^\%(\\s\)\{5}/>
Best,
Christian
Is there another soluce because the file can contains several indent
level:
\s\s\s\s\sFOO
BAR1
BAR2
END_OF_BLOCK
\s\s\s\s\sFOO2
BAR1
BAR2
END_OF_BLOCK
\s\s\s\s\s\s\s\s\sFOO3
BAR1
BAR2
END_OF_BLOCK
\s\s\sFOO2
BAR1
BAR2
END_OF_BLOCK
Adjust the regular expression ;)
:v/^\%(\\s\)\+/>
That will indent each line, that does *not* start with '\s' by one
shiftwidth.
Does that help you?
Best,
Christian
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