Ok thank you and sorry for my english.
On Tuesday, June 10, 2014 7:38:18 PM UTC+2, Tim Chase wrote:
> On 2014-06-10 07:13, Ben Fritz wrote:
>
> > > It works a little using \s out \\s because I have magic card I
>
> > > think:
>
> > >
>
> > > :g/^\s/exec 'sil! +,/^END_OF_BLOCK/'.repeat('>',
>
> > > strlen(matchstr(getline('.'), '\(\s\)\+')) / 2)
>
> > >
>
> > >
>
> > > In fact I got :
>
> > >
>
> > > <some\spaces>THE_LINE_OF_THE_HEADER_THREE
>
> > > OTHER DEPEND'S LINES
>
> > > OTHER DEPEND'S LINES
>
> >
>
> > You were SPECIFICALLY ASKED whether all your \s examples were two
>
> > literal '\' and 's' characters, or whether they were spaces. You
>
> > said:
>
>
>
> Which would adjust the command, so you're remove the "/2" because
>
> that divides by the number of characters found. With a literal "\s",
>
> that's two characters, so you need to divide the length by 2. If
>
> there's only one character as found by the regexp "\s", then it's
>
> effectively dividing by 1 which is a no-op.
>
>
>
> -tim
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