Hi Nick! On Di, 30 Dez 2014, Nick Gieschen wrote:
> If I try set iskeyword-=a it doesn't actually work. That is, the char a is > still seen as part of a word. Can someone tell me the rules for what chars > cannot be removed from the keyword list? Check the actual setting of your 'isk'. It probably looks like this: @,48-57,_,192-255 Note, the '@' which means all alphanumeric characters. Therefore, issuing :set isk-=a won't work (since the 'a' is not included, it can't be removed). To explicitly remove the 'a', use :set isk+=^a Read the gory details of the syntax at :h 'isfname' Please also note, that changing this option is not advised and even if you do it, you should probably only change it for the current buffer, e.g. use :setlocal instead of :set. Best, Christian -- Wie man sein Kind nicht nennen sollte: Pia Nist -- -- You received this message from the "vim_use" maillist. Do not top-post! Type your reply below the text you are replying to. For more information, visit http://www.vim.org/maillist.php --- You received this message because you are subscribed to the Google Groups "vim_use" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
