Resolved -- the interloper vi (i.e., what was executed when vi was called in bash) was a vi that bash had hashed rather than the vi that was currently in the PATH.

Extract from replies: `which` does not report on what bash will execute; `type` does. Although `type` provides info on whether the command is hashed or not, `type -a` does not. `hash -r` clears the hash.

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