Hi Eric,
I don’t quite follow what you are asking as both queries you provide are the
same whereas you imply they should be different ? Anyway the query with the
distinct you indicate returns 0 rows for you returns 2 rows for me:
SQL> rdfs_rule_set ('ifps', 'ifp_list');
Done. -- 230 msec.
SQL> SPARQL define input:inference "ifps" SELECT * FROM <ifps> WHERE {<john1>
?p ?o};
p
o
VARCHAR
VARCHAR
_______________________________________________________________________________
http://www.w3.org/1999/02/22-rdf-syntax-ns#type
person
http://www.w3.org/2002/07/owl#sameAs
john2
name
John
name
Tarzan
address
101 A street
http://www.w3.org/1999/02/22-rdf-syntax-ns#type
person
name
John
address
102 B street
knows
mike
9 Rows. -- 134 msec.
SQL> SPARQL define input:inference "ifps" SELECT distinct ?p FROM <ifps> WHERE
{ ?p a <person>};
p
VARCHAR
_______________________________________________________________________________
john1
mary
mike
3 Rows. -- 123 msec.
SQL> SPARQL define input:inference "ifps" SELECT DISTINCT * FROM <ifps> WHERE
{?person <name> ?name};
person
name
VARCHAR
VARCHAR
_______________________________________________________________________________
john1
John
john1
Tarzan
2 Rows. -- 214 msec.
SQL>
As you are running a 6.1.2 build which is over a year old (probably from a
Linux Distro ???), I would suggest you update your build to the latest snapshot
6.1.4 RC1 available from:
ftp://download.openlinksw.com/support/vos/virtuoso-opensource-6-20110915.tar.gz
and repeat your test ...
Best Regards
Hugh Williams
Professional Services
OpenLink Software
Web: http://www.openlinksw.com
Support: http://support.openlinksw.com
Forums: http://boards.openlinksw.com/support
Twitter: http://twitter.com/OpenLink
On 13 Oct 2011, at 03:00, Eric Rozell wrote:
> Hi Virtuoso team,
>
> (Sorry for the repeat emails.)
>
> I'm using Virtuoso for a project and have a simple RDFS inferencing use case.
> Rather than giving you the details of the use case, I replicated the error
> for one of the examples on the RDFS inferencing page
> (http://docs.openlinksw.com/virtuoso/rdfsparqlrule.html). Specifically, I am
> working off of the example in section 16.13.9 Identity With Inverse
> Functional Properties.
>
> I need to perform a SELECT DISTINCT query using literal values in this data
> with a single query. So, going on the example given, my query might look
> like:
>
> SQL>SPARQL define input:inference "ifps" SELECT DISTINCT * FROM <ifps> WHERE
> {?person <name> ?name};
>
> If I execute the query, I get no results (see below):
>
> person
> name
> VARCHAR
> VARCHAR
> _______________________________________________________________________________
>
>
> 0 Rows. -- 2 msec.
>
>
> If I execute the query without the DISTINCT constraint, I get results (see
> below):
>
> SQL>SPARQL define input:inference "ifps" SELECT DISTINCT * FROM <ifps> WHERE
> {?person <name> ?name};
>
> person
> name
> VARCHAR
> VARCHAR
> _______________________________________________________________________________
>
> john1
> John
> john2
> John
> john1
> Tarzan
>
> 3 Rows. -- 1 msec.
>
> Given the results from the second query, I would expect the same results for
> a SELECT DISTINCT query. Any thoughts on what is causing this error? I am
> using Virtuoso 6.1.2.
>
> Thanks,
> -Eric Rozell
>
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