Hi all !
I have tried to get the resource http://dbpedia.org/resource/Film
when asking for "film" in the indexes in http://dbpedia.org/sparql, in
several ways:
SELECT DISTINCT ?s ?o FROM <http://dbpedia.org> WHERE {{?s rdfs:label
?o.[] a ?s .FILTER( bif:contains(?o, "film" ) )}}LIMIT 36
SELECT DISTINCT ?s ?o ?type FROM <http://dbpedia.org> WHERE {{?s
rdfs:label
?o. ?s rdf:type ?type .FILTER( bif:contains(?o, "film" ) )}}LIMIT 36
And even:
SELECT ?s ?page ?label
?textScore AS ?Text_Score_Rank
( <LONG::IRI_RANK> (?s) ) AS ?Entity_Rank
WHERE
{
?s foaf:page ?page ;
rdfs:label ?label .
FILTER( lang( ?label ) = "en" ) .
?label bif:contains 'film'
OPTION (score ?textScore ) .
}
ORDER BY ASC ( <LONG::IRI_RANK> (?s) )
But with no success so far.
I also tried:
SELECT DISTINCT ?s ?o ?type FROM <http://dbpedia.org> WHERE {{?s
rdfs:label
?o. ?s rdf:type ?type .FILTER( str(?o) = "Film" ) }}
But it gives an out of time error ..
Any idea how can I get http://dbpedia.org/resource/Film from the
keyword "film"?
Thanks a lot
Vanessa
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