On 07/04/2011 06:00 PM, Ivan Mikhailov wrote:
> Hello Sebastian,
> If ?app always gets exactly one value, what's the purpose in the
> subquery?
>
> If you're not sure that ?app is the only (e.g., if triple ?app
> nao:identifier "nepomukindexer" can appear in more than one graph), then
> you can write, of course,
>
> select distinct ?r where {
> graph ?g {
> ?r nie:url ?url .
> } .
> ?g nao:maintainedBy ?app .
> filter (?app = (select ?a where { ?a nao:identifier "nepomukindexer" }))
> }
>
> or even shorter
>
> select distinct ?r where {
> graph ?g {
> ?r nie:url ?url .
> } .
> ?g nao:maintainedBy `(select ?a where { ?a nao:identifier
> "nepomukindexer" })` .
> }
perfect. This is exactly what I was looking for. Thanks. :)
Cheers,
Sebastian
>
> Best Regards,
>
> Ivan Mikhailov
> OpenLink Software
> http://virtuoso.openlinksw.com
>
>
> On Mon, 2011-07-04 at 14:42 +0200, Sebastian Trüg wrote:
>> Hi list,
>>
>> in a query like this:
>>
>> select distinct ?r where {
>> graph ?g {
>> ?r nie:url ?url .
>> } .
>> ?g nao:maintainedBy ?app .
>> ?app nao:identifier "nepomukindexer" .
>> }
>>
>> I would like to use a sub-query to replace ?app since there is only
>> exactly one resource which has this identifier. The simplest possibility
>> is to use two queries and cache the resource URI of the app in the
>> client. But I figure there could be a fancy sub-query which allowed me
>> to query the app in-place.
>>
>> Is that possible?
>>
>> Cheers,
>> Sebastian
>>
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>
>
>