On 5/3/12 1:08 PM, Hugh Williams wrote:
Hi Alex,

Are you able to provide some sample data for the inference rule you are creating and the datasets it is being applied against so we can follow a set of steps to recreate this problem in-house ? Or if you can recreate on one of our public SPARQL endpoints that would be helpful also as in both case we have a test case to look into and resolve the issue if required ?

Alex,

In our earlier exchanges, I forgot to mention to you the fact that a number of our public facing sparql endpoints can be used as problem recreation beds. In your case, assuming you are using the RDFS Schema as your inference rule, you can simply make use of our preset inference rules. Here's what you need to do:

1. Goto to one of the endpoints
2. Select an inference rule
3. Use the selected inference rule in a sparql query scoped to an existing named graph IRI or use the sponger feature (via FROM CLAUSE (option get:soft "add" ) or define get:soft "add" pragma) .

Possible endpoints:

1. http://demo.openlinksw.com/sparql
2. http://uriburner.com/sparql .

Rule name for RDFS Schema is "RDFs" , and its based on the ontology at: http://www.w3.org/2000/01/rdf-schema . Thus, you are going to be executing:

Data Creation:

sparql
define get:soft "add"
define input:inference "RDFs"
insert {graph <rdfs_g> {?s ?p ?o}}
using <g> where {?s ?p ?o}

and

sparql
define get:soft "add"
define input:inference "RDFs"
insert {graph <rdfs_g> {<uri> ?p ?o}}
using <g> where {<uri> ?p ?o}

then make your sample queries that demonstrate the problem in question.

Kingsley





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Hugh Williams
Professional Services
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On 3 May 2012, at 15:19, Alex wrote:

Hello,
so the referred problem also exists in the 6.1.5 version.
This time I tried the following queries w.r.t Sparql 1.1:

sparql define input:inference<something> insert {graph <rdfs_g>{<uri>
?p ?o}} using <g> where{<uri> ?p ?o}; (1)

sparql define input:inference<something> insert {graph <rdfs_g>{?s ?p
?o}} using <g> where{?s ?p ?o}; (2)

Using the following query:
sparql select * from <rdfs_g> where{<uri> ?p ?o};

The result after (1) is different than those after (2).

The tests regards the number of inferred triples and a requirement is
backward chaining.
I cannot have a "safe" outcome with the above behavior.

I know that virtuoso is huge and maybe requires a lot of work.
However, I am not so sure if I have enough time anymore.
The deadlines are chasing me and I am afraid I should change triple store.


On 27 April 2012 18:52, Kingsley Idehen <[email protected] <mailto:[email protected]>> wrote:
On 4/27/12 10:18 AM, Alex wrote:

Thank you for your support.

Two more things to take into consideration on the previous statistics.

Even though the total number of triples in<rdfs_g>  and<g>  might be 8
and that there is 1 class instance in both graphs this does not mean
that the triples are the same in<rdfs_g>  and<g>,
e.g., the triple (<uri>  rdf:type ?o) is different in<g>  and in
<rdfs_g>  w.r.t ?o (i.e., 2 different class instances, where in
<rdfs_g>  is only one inferred).

Moreover, I have installed 06.01.327 version on ubuntu. Meanwhile I do not
promise that I will upgrade virtuoso (maybe only after an official
response) because of the possible danger of
messing up with the dataset and/or current configuration.


Please upgrade as this helps resolution of this matter.

You can dump your dataset and then reload into the upgraded instance.

You can also make backup and restore.


Kingsley


On 27 April 2012 16:57, Kingsley Idehen<[email protected] <mailto:[email protected]>> wrote:

On 4/27/12 9:31 AM, Alex wrote:

Yes rdfs schema.

15 is the total number of triples including both the inferred and the
explicit ones from<g>.


Okay, I am going to hand this over to our support team to see if they can
recreate based on the information in this post. Naturally, you have to
bear
with the support turnaround which is always based on what's on the queue
etc..

They (or I) will get back to you.


Kingsley


On 27 April 2012 15:45, Kingsley Idehen<[email protected] <mailto:[email protected]>>
 wrote:

On 4/27/12 8:36 AM, Alex wrote:

I can give you some statistics if this is helpful.

Number of triples in<g>: 152329
Number of triples with subject<uri>      in<g>: 8
Number of triples with subject<uri>      in<rdfs_g>      : 8
Number of triples applying rdfs on triples with subject<uri>
 in<g>:
15


I assume you are using rdfs schema for your inference rule? If true, I
also
assume 15 is the inferred triples count?


Kingsley

sparql define input:inference<something> select count(*) from<g>
where{?s ?p ?o} : 152329 !
sparql define input:inference<something> select count(*) from<g>
where{<uri>      rdf:type ?o} : 1
sparql define input:inference<something>      select count(*)
from<rdfs_g>
where{<uri>      rdf:type ?o}: 1

sparql clear graph<rdfs_g>
sparql define input:inference<something>      insert into<rdfs_g>
{<uri>?p ?o} where{graph<g>      {<uri>      ?p ?o}}
sparql define input:inference<something>      select count(*) from
<rdfs_g>      where{<uri>      rdf:type ?o}: 6

I hope there will be no typos. Do you need anything else to share with
you? Please let me know.

Thanks.

On 27 April 2012 15:05, Kingsley Idehen<[email protected] <mailto:[email protected]>>
 wrote:

On 4/27/12 7:35 AM, Alex wrote:

Following the Carina's advice:

shutdown()
change value of parameter "ResultSetMaxRows" in the .ini file to
1000000000000000
save
sudo virtuoso-t -f&
sudo isql-vt

Applying again the rule, I get same the wrong behavior: inference
only
on the<uri> results to the correct inferred triples, but not
in
the
case of inference on the whole dataset.

I think and I am afraid I cannot "share" the dataset I am testing (
if
you meant that).

I changed my query to selection:

sparql define input:inference<something>        select * from<g>
 where{?s
?p
?o} limit 20

I do not know how the inference is evaluated on the triples and how the result is returned, but in the first 20 results I do not see any
new inferred triple.


Without sharing a SPARQL URL you can share the results of a SELECT
query
e.g., a count of the records when using a SELECT query.

Kingsley

On 27 April 2012 14:18, Kingsley Idehen<[email protected] <mailto:[email protected]>>
 wrote:

On 4/27/12 6:57 AM, Carina Haupt wrote:


On 27.04.2012 12:14, Alex wrote:

Hello again,
my scenario is the following: given a graph<g>           with
some
triples
apply a rule set based on a schema and insert the inferred
triples
to
another graphs<rdfs_g>.

So I use the following query to accomplish that:

sparql define input:inference<something>           insert
into<rdfs_g>
{?s ?p
?o} where{graph<g>           {?s ?p ?o}} (1)

I then check for a specific uri in rdfs_g and I see the same
inferred
triples but NOT all of them and the number of triples is the
same.

To further test it I apply the same rule for this specific uri:

sparql define input:inference<something>           insert
into<rdfs_g>
{<uri>
?p ?o} where{graph<g>           {<uri>           ?p ?o}} (2)

Comparing the<rdfs_g>           to<g>           there is big
difference
on
the
number of
triples (i.e. 15 to 8 rows respectively) and I think I see the
total
inferred triples.

What is wrong with that?? I have test it (1) on a smaller dataset
that
<g>           and works fine.

I am begging to lose my mind on this. How could I debug this?

There is a threshold in the ini file which defines how many
triples
are
returned at max. Perhaps this is the source of your problem?!

Ciao Carina


Yes re. INI.

Alternatively, one diagnostic option re. assistance from us would
be
to
change the INSERT into a SELECT and then share the SPARQL protocol
URL.

Kingsley

Thanks.






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