On 2/4/14 6:46 AM, "Nádudvari Gyuri (Reedcourty)" wrote:
Hi Everybody,I have a problem with the SPARQL engine of Virtuoso. I want to use it with the next ontology: <?xml version="1.0"?> <rdf:RDF xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"; xmlns:owl="http://www.w3.org/2002/07/owl#"; xmlns:xsd="http://www.w3.org/2001/XMLSchema#"; xmlns="http://reedcourty.github.com/ontologies/tags#"; xmlns:rdfs="http://www.w3.org/2000/01/rdf-schema#"; xml:base="http://reedcourty.github.com/ontologies/tags";> <owl:Ontology rdf:about=""> <owl:versionInfo rdf:datatype="http://www.w3.org/2001/XMLSchema#string"; >Created with TopBraid Composer</owl:versionInfo> </owl:Ontology> <owl:Class rdf:ID="Tag"> <rdfs:subClassOf rdf:resource="http://www.w3.org/2002/07/owl#Thing"/> </owl:Class> <owl:Class rdf:ID="FieldNameInDB"> <rdfs:subClassOf rdf:resource="#Tag"/> </owl:Class> <owl:ObjectProperty rdf:ID="tagging"> <rdfs:range rdf:resource="http://www.w3.org/2002/07/owl#Thing"/> <rdfs:domain rdf:resource="#Tag"/> <rdfs:comment rdf:datatype="http://www.w3.org/2001/XMLSchema#string"; >The tag tagging a Thing</rdfs:comment> <owl:inverseOf> <owl:ObjectProperty rdf:ID="taggedBy"/> </owl:inverseOf> </owl:ObjectProperty> <owl:ObjectProperty rdf:about="#taggedBy"> <owl:inverseOf rdf:resource="#tagging"/> <rdfs:range rdf:resource="#Tag"/> <rdfs:comment rdf:datatype="http://www.w3.org/2001/XMLSchema#string"; >The Thing tagged by a Tag</rdfs:comment> <rdfs:domain rdf:resource="http://www.w3.org/2002/07/owl#Thing"/> </owl:ObjectProperty> <rdf:Property rdf:ID="hasComment"> <rdfs:range rdf:resource="http://www.w3.org/2001/XMLSchema#string"/> <rdfs:domain rdf:resource="#Tag"/> <rdfs:comment rdf:datatype="http://www.w3.org/2001/XMLSchema#string"; >The tag has a comment</rdfs:comment> </rdf:Property> <rdf:Property rdf:ID="addedBy"> <rdfs:domain rdf:resource="#Tag"/> <rdfs:range rdf:resource="http://www.w3.org/2001/XMLSchema#string"/> <rdfs:comment rdf:datatype="http://www.w3.org/2001/XMLSchema#string"; >Added by somebody</rdfs:comment> </rdf:Property> <rdf:Property rdf:ID="hasName"> <rdfs:domain rdf:resource="#Tag"/> <rdfs:range rdf:resource="http://www.w3.org/2001/XMLSchema#string"/> <rdfs:comment rdf:datatype="http://www.w3.org/2001/XMLSchema#string"; >The tag has a name</rdfs:comment> </rdf:Property> <rdf:Property rdf:ID="addedAt"> <rdfs:domain rdf:resource="#Tag"/> <rdfs:range rdf:resource="http://www.w3.org/2001/XMLSchema#dateTime"/> <rdfs:comment rdf:datatype="http://www.w3.org/2001/XMLSchema#string"; >E.g. the tag added at "2013-10-10T095100"</rdfs:comment> </rdf:Property> </rdf:RDF> I had uploaded the RDF file to Virtuoso via it's webdav service. Then I used the following query (but by using others I got the same result): PREFIX tags:<http://reedcourty.github.com/ontologies/tags#> SELECT ?tag WHERE { ?tag rdfs:subClassOf tags:Tag . } The problem is that I got back every item twice, like: http://reedcourty.github.com/ontologies/tags#FieldNameInDB http://reedcourty.github.com/ontologies/tags#FieldNameInDB What is the problem? I'm using Virtuoso version 07.00.3203 on Win64 (x86_64-generic-win-64), Single Server Edition
The problem is that you have two documents (denoted by named graph IRIs) in your Virtuoso instance that are comprised of the same (or overlapping) RDF statements (triples).
You can see this via: PREFIX tags:<http://reedcourty.github.com/ontologies/tags#> SELECT ?tag ?g WHERE { GRAPH ?g { ?tag rdfs:subClassOf tags:Tag . } } You can fix using: PREFIX tags:<http://reedcourty.github.com/ontologies/tags#> SELECT DISTINCT ?tag WHERE { GRAPH ?g { ?tag rdfs:subClassOf tags:Tag . } } or by using PREFIX tags:<http://reedcourty.github.com/ontologies/tags#> SELECT DISTINCT ?tag WHERE { GRAPH <{named-graph-iri}> { ?tag rdfs:subClassOf tags:Tag . } } -- Regards, Kingsley Idehen Founder & CEO OpenLink Software Company Web: http://www.openlinksw.com Personal Weblog: http://www.openlinksw.com/blog/~kidehen Twitter Profile: https://twitter.com/kidehen Google+ Profile: https://plus.google.com/+KingsleyIdehen/about LinkedIn Profile: http://www.linkedin.com/in/kidehen
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