Hello all,
I am using the update versions from "uk.research.at.com". When I use Java
Applet from IE or Netscape to connect to a PC(windows 2000), it has an error
message " com.ms sedurity.SecurityExcepionEx[rfbProto.<init>]: cannot access
"192.9.200.69". 5900". Can someone tell me how to solve this problem? But it
works fine from VNCWindow or Dos windows by running command:
C:\1 x\New Folder\tightvnc-1.1p9_javabin\classes>java vncviewer HOST
192.9.200.69 PORT 5900
Here is the HTML page that I used to connect the PC with the connection
ERROR.
<html>
<head>
<title>VNCviewer</title>
</head>
<body>
<h1>VNCviewer for eValid</h1>
<hr>
<applet codebase="." applet code="vncviewer.class"
ARCHIVE=vncviewer.jar WIDTH=800 HEIGHT=600>
<param name="HOST" value="192.9.200.69">
<param name="PORT" value="5900">
<param name="Encoding" value="evalid">
<param name="Use CopyRect" value="Yes">
<param name="Mouse buttons 2 and 3" value="Normal">
<param name="Raw pixel drawing" value="Reliable">
<param name="CopyRect" value="Fast">
<param name="Share desktop" value="Yes">
</APPLET>
</body>
</html>
Thanks.
--Tony
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