RE: [Vo]:Hydrogen may not be needed - Spitaleri and others explain Lithium fusionJones--
Thanks for that clarification. I would say two or more bosons together make a cluster so that upon coming out of coherence they appear as an alpha and two positrons. I have never heard the assertion that statistics that permit clustering also deplete nuclear mass. I would think that the binding energy of a Cooper pair of H's would add to the mass of the pair compared to the sum of the masses of the 2 free H's. Bob ----- Original Message ----- From: Jones Beene To: [email protected] Sent: Friday, March 20, 2015 2:36 PM Subject: RE: [Vo]:Hydrogen may not be needed - Spitaleri and others explain Lithium fusion From: Bob Cook Ø What about clusters of H nuclei--like Coopers pairs--moving about in the same lattice site. He is using a different meaning for "clusters," it seems. More like a small condensate. For instance, and as I understand it - on occasion there are naturally as a result of statistics, three "clusters" in a Li-6 nucleus, and they look and act like 3 separate but coherent deuterons. Therefore these resemble a condensate of 3 deuterons which then transition back to the normal nucleus where they spend 99.99+ percent of their time. The short-lived cluster only happens on a transitory basis at high temperature. When two lithium-6 nuclei approach each other, on the rare occasion that they both condense at the same time to interact as a cluster of 6 deuterons, then this is identical to all of them being condensed in the sense of nuclear bosons, so that when they come out of coherence, due to thermal effects - then they can come out as 3 alphas (helium nuclei). BUT. there is much less enthalpy than normal, since the statistics which permit the clustering, also deplete nuclear mass. Therefore the three alphas do not have anywhere near the expected excess energy, but it is still large compared to chemical The way to validate this is to find helium in the ash. It is pretty much that simple, and it explains cold fusion not as fusion of deuterons but as fusion of Li-6 in the electrolyte. Jones
