In reply to  Jones Beene's message of Wed, 10 May 2006 07:21:33
-0700 (PDT):
Hi Jones,
[snip]
>Yes, as I was about to say .... <g>.... hydrinos are
>likely to be involved but as an "agent" for an Auger
>cascade methodology, and perhaps not in the way you
>are suggesting, based on Mills' published experiments.
[snip]
Negative muons orbit at the Bohr radius (BR) * electron mass /
muon mass. Hence hydrinohydride should try to do the same, i.e.

BR * electron mass / hydrino mass, however this works out to a
distance from the nucleus of only about 29 F. 

Problem # 1: According to Mills, the lowest level at which hydrino
hydride can exist is p=24 (?). At which level it has a radius of 

BR / 24 = 2205 F according to Mills, and BR/(24^2) = 91.8 F
according to me.

Either way, it is larger than the distance at which it should
orbit. This leaves several possible scenarios:-

1) It sits snug against the nucleus at it's own radius.
2) It shares it's shrunken electrons with the other nucleus in a
covalent bond at very small radius (don't know how big), but it
would have to be smaller than it's own radius or there wouldn't be
any energy benefit in forming the bond.
3) It loses it's shrunken electrons to the heavier nucleus
altogether, and is expelled from the heavier atom with extreme
prejudice (possibly stealing a normal electron on the way out in
revenge).
4) Is welcomed into the nucleus in a fusion reaction.

BTW for the Auger scenario to play out, it would seem to me that
one would have to put as much energy into the compound atom to
dislodge the hydrino hydride as was initially released when it
entered. This would have to be more energy than the Auger cascade
frees, because those electrons were initially pushed up a level
when the hydrino hydride entered in the first place (reverse Auger
cascade), which wouldn't have happened unless the hydrinohydride
bonding energy with the K nucleus were greater than the energy of
the reverse Auger cascade.

Regards,

Robin van Spaandonk

http://users.bigpond.net.au/rvanspaa/

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Cooperation provides the means.

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