At 04:44 PM 10/6/2011, Man on Bridges wrote:
Ok now try to squeeze these mice in the smallest possible space and
assume the tails can be placed between the mice requiring no extra
space in the volume in a L*B*H box.
This results in (10 * 8.5 cm) * (30 x 3 cm) * (20 x 3 cm) + (1 * 8.5
cm) *(1 * 3 cm) * (30 * 3 cm ) , this means these 6030 mice (Hey, we
don't like partial mice ;-) )need a volume of approx. 461 liter and
have a weight of 142 kg.
Rest to Active metabolism is 8X
OK .. to allow breathing room ... take 461/8 = 57 liters.
COULD be mouse-powered ....
