Ed--Bob here--
The protons are fermi particles with a spin of 1/2, so 2 protons would
create a new particle spin of 1 plus the 1/2 from the electron for a total
of +1-1/2.
I think deuteron's are Bose particles with a spin of 0. Correct me if I am
wrong.
What happens to the excess spin?
Bob
-----Original Message-----
From: Edmund Storms
Sent: Thursday, February 13, 2014 6:30 AM
To: [email protected]
Subject: Re: [Vo]:Re: a note from Dr. Stoyan Sargoytchev
Bob, these three particles create a deuteron after all of the excess mass
energy has been emitted as photons. The neutrino has very little energy
because very little remains when the d forms. The creation process is unique
to lenr and applies to all the isotopes of hydrogen, at least that is my
model. if lenr is to be explained, you need to stop thinking in conventional
terms. This is a new kind of nuclear process.
Ed Storms
Sent from my iPad
On Feb 12, 2014, at 3:00 PM, "Bob Cook" <[email protected]> wrote:
Jones--Bob Cook Here--
Can you show how the p-e-p reaction as you understand it conserves spin?
I would think that the newly fused particle, whatever it is, would have
1/2 or 3/2 spin--I do not know.
If a positron is emitted, its spin would be -1/2 I think. That would
make the new particle have 0 or 1 spin.
The reaction of the positron and electron give photons with 0 spin.
Bob
.
-----Original Message----- From: Jones Beene tt
Sent: Wednesday, February 12, 2014 1:10 PM
To: [email protected]
Subject: RE: [Vo]:a note from Dr. Stoyan Sargoytchev
-----Original Message-----
From: [email protected]
The most elegant answer begins with the obvious assertion that there are
no
gammas ab initio, which means that no reaction of the kind which your
theory
proposes can be valid because gammas are expected.
Actually not only would I not expect to detect any gammas from a p-e-p
reaction, I wouldn't expect to detect any energy at all. That's because
the
energy of the p-e-p reaction is normally carried away by the neutrino,
which
is almost undetectable.
Hi,
Not so - the reaction produces a positron, which annihilates with an
electron producing 2 gammas. They net energy is over 1 MeV and easily
detectable.
Jones
