Cold Fusion exists for PdD. What is not proven is NiH fusion.

2014-05-18 3:46 GMT-03:00 Kevin O'Malley <[email protected]>:

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> Here's an old discussion I had on an intrade board about the "probability
> of Rossi being real"
>
>
>
> http://intrade.freeforums.org/i-miss-intrade-t29.html
>
>  Re: I miss 
> Intrade<http://intrade.freeforums.org/i-miss-intrade-t29.html#p138>
>
> [image: Post] <http://intrade.freeforums.org/post138.html#p138>by *intrader
> <http://intrade.freeforums.org/memberlist.php?mode=viewprofile&u=70>* ยป
> Mon May 27, 2013 2:12 am
> Third time is the charm:
>
> P(A|B) = P(B|A) * P(A) / P(B)
> or
> P(B) = P(B|A) * P(A) / P(A|B)
>
> A = E-Cat & Rossi is real
> B = Cold fusion (or something close to it) is discovered
>
> If E-Cat is real, it looks like cold fusion to me (or something close to
> it). P(B|A) = 0.5
> I think we all can go with the prior probability that E-Cat & Rossi was
> probably not real (history of fraud / was convicted / etc) P(A) = 0.01
>
> Now, what is the probability that if cold fusion exists that it's going to
> be Rossi that makes a real e-cat?
>
> Interestingly, the more we disparage Rossi (relative to his colleagues)
> here, the more likely cold fusion exists.
>
> Unfortunately, I think only people like Rossi are actually looking at cold
> fusion. So if it does exists, I think it's reasonable to say it'll be Rossi
> or perhaps someone like Rossi that might discover it. So, P(A|B) = 0.05 (I
> think it's fair to say at least 20 other people are looking at it).
>
> However, if it looks like more people of Rossi's caliber or better are
> looking at Cold Fusion, then that bodes well for CF. So, go ahead and punch
> in your own number there.
>
> Counter intuitive, kinda, but that's bayes for you.
>
>
> So, P(B) = (0.5 * 0.01) / 0.05 = 25% cold fusion exists.
>
>
>


-- 
Daniel Rocha - RJ
[email protected]

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