In reply to Jones Beene's message of Mon, 22 Sep 2014 16:32:02 -0700: Hi, [snip] >The usual "lame" rationalizations we have used is that the energy was >borrowed in advance to overcome the Coulomb barrier or shed in advance to >achieve the redundancy ... > >But you're right - fusion numbers simply don't work well for the reality of >a Rossi type reaction, as there is too much excess energy to hide... and >this rationalization is no better than the factionalized gamma. > >So there you have it... back to "no-fusion in LENR" it is...
I would still be inclined to consider reactions that produce heavy charged particles. The heavier and slower, the better. E.g. fusion/fission reactions. I think the secondary gammas from heavily charged slow moving daughter nuclei might have been shielded. One possibility is the p-B11 reaction which produces quite low energy alphas because there are three of them. Furthermore the double charge on the alpha particles means both rapid energy loss to electrons, and strong repulsion from other nuclei, thus strongly reducing the chances of creating secondary gammas. Also, if such a reaction were to occur within the mass of the Boron, then the short range of the alphas would mostly keep them in the Boron itself, and the lowest excited state of B11 is 2.1247 MeV. This is not much less than the energy of the alphas, so in order to produce any secondary gammas at all, such an alpha would need to collide directly with another B11 nucleus almost immediately after creation, i.e. before it lost too much energy through ionization. That thus works to reduce the intensity of any secondary radiation. (B10 OTOH has excited states at 718 & 740 keV, but then B10 is only 20% of natural Boron). Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
