I agree, you really can tell where that Li6 came from should read
I agree, you really can not tell where that Li6 came from On Wed, Oct 8, 2014 at 10:35 PM, Axil Axil <[email protected]> wrote: > I agree, you really can tell where that Li6 came from. > > On Wed, Oct 8, 2014 at 10:21 PM, <[email protected]> wrote: > >> In reply to Jones Beene's message of Wed, 8 Oct 2014 09:22:13 -0700: >> Hi, >> [snip] >> >> Li7 + Ni58 => Ni59 + Li6 + 1.75 MeV >> Li7 + Ni59 => Ni60 + Li6 + 4.14 MeV >> Li7 + Ni60 => Ni61 + Li6 + 0.57 MeV >> Li7 + Ni61 => Ni62 + Li6 + 3.34 MeV >> Li7 + Ni62 => Ni63 + Li6 - 0.41 MeV (Endothermic!) >> >> This series stops at Ni62, hence all isotopes of Ni less than 62 are >> depleted >> and Ni62 is strongly enriched. >> >> I have only briefly skimmed the report, but the basic reaction appears to >> be a >> neutron transfer reaction where a neutron tunnels from Li7 to a Nickel >> isotope. >> The excess energy of the reaction appears as kinetic energy of the two >> resultant >> nuclei (i.e. Li6 & the new Ni isotope), rather than as gamma rays. >> Because there >> are two daughter nuclei, momentum can be conserved while dumping the >> energy as >> kinetic energy in a reaction that is much faster then gamma ray emission. >> Because both nuclei are "heavy" and slow moving, very little to no >> bremsstrahlung is produced. There is effectively no secondary gamma from >> Li6 >> because the first excited state is too high. (I haven't checked Li7). >> There is >> unlikely to be anything significant from Ni because the high charge on the >> nucleus combined with the "3" from Lithium tend to keep them apart >> (minimum >> distance 31 fm). >> >> It would be nice to know if the total amounts of each of Li & Ni in the >> sample >> were conserved (I'll have to study the report more closely). >> Regards, >> >> Robin van Spaandonk >> >> http://rvanspaa.freehostia.com/project.html >> >> >
