Jones Beene wrote:
By that, it is meant that if you direct converter shows an electrical output of 500 milliwatts from a laser beam of 50 milliwatts, then those results stand by themselves without all the questions which can come up when calorimetry is used.
But the laser is notoriously inefficient. It can easily take 500 milliWatts of input to get 50 milliWatts of laser energy.
