Hi Horace.

Your posts are like a fine French cheese, they need to age
a bit before reaching the peak of flavour... Are we there yet?

Anyway, as you seem to be taking some liberties
with your models, let me try this notion on you.

Let's question the assumption of 3 quantum variables.
String theory suggests that more than our 3 visible
dimensions exist; the number varying depending on the
theory, time of day, etc. Consider for a moment
the case of four dimensions...

A       B       C       D       E       F       G       H
0       0       0       0       1       1       1       1
0       0       0       1       1       1       1       0
0       0       1       0       1       1       0       1
0       0       1       1       1       1       0       0
0       1       0       0       1       0       1       1
0       1       0       1       1       0       1       0
0       1       1       0       1       0       0       1
0       1       1       1       1       0       0       0
1       0       0       0       0       1       1       1
1       0       0       1       0       1       1       0
1       0       1       0       0       1       0       1
1       0       1       1       0       1       0       0
1       1       0       0       0       0       1       1
1       1       0       1       0       0       1       0
1       1       1       0       0       0       0       1
1       1       1       1       0       0       0       0

AE 16/16
AF 8/16
AG 8/16
AH 8/16
BE 8/16
BF 16/16
BG 8/16
BH 8/16
CE 8/16
CF 8/16
CG 16/16
CH 8/16
DE 8/16
DF 8/16
DG 8/16
DH 16/16

4 matches over 16 combinations
4*16 + 12*8

160/256 = .625

Getting closer to our magic .5, but not there yet...
Let's try 6 dimensions.

-snip huge table-

16 full matches over 256 combinations

16*256 + 240*128
4096 + 30720

34816/65536 = .53125

Closer and closer...

Now 8 dimensions

256 full matches over 65536 combinations

-snip ungodly huge table-

.502

The more dimensions we add, the closer we get. What
do you think? If you think this is cheating ( and
maybe it is ) where is the assumption of only 3
quantum variables coming from ( other than our
much beleagured common sense ).

K.

-----Original Message-----
From: Horace Heffner [mailto:[EMAIL PROTECTED]
Sent: Sunday, October 17, 2004 2:08 PM
To: [EMAIL PROTECTED]
Subject: Re: EPR and Bell Revisited (DRAFT #6)


                  EPR and Bell Revisited (DRAFT #6)

Assume, as did Einstein, Podolski, and Rosen (EPR), the state of conjugate
entangled particles is set at the time of the creation of the conjugates,
at the moment of entanglement.  EPR maintained that entangled particles in
effect carry hidden variables, or an equivalent of a computer program, that
determines how they will act when observed.  Assume there are, as in Alain
Aspect's experiment designed to examine this assumption, three independent
quantum values involved.  That is to say there are three axes of spin
observation, in which a particle is in either a clockwise or
counterclockwise spin state upon observation.  Unfortunately, spin can only
be observed in one axis, not all three at the same time.  However, Bell
figured out how to see if the quantum variables were set before
measurement, i.e. how to see if a hidden variable was involved.  The
situation is shown in Table 1, below.


i A B C D E F

1 0 0 0 1 1 1    Key:
2 0 0 1 1 1 0
3 0 1 0 1 0 1    i - possible combination (row) number
4 0 1 1 1 0 0    A, B, C - Alice's possible observations
5 1 0 0 0 1 1    D, E, F - Bob's corresponding observations
6 1 0 1 0 1 0
7 1 1 0 0 0 1
8 1 1 1 0 0 0


Table 1 - Possible observations by Alice and Bob


Table 1 assumes that when an entangled particle pair is created that all
three quantum variables, i.e. spins, are set at that time and carried as
"hidden variables".  Columns A, B and C are possible spins observed by a
sender Alice in orthogonal axes A, B and C, and are denoted "o" for
clockwise spin and "1" for counterclockwise spin. Columns D, E, and F are
the corresponding spins observed by receiver Bob in the axes A, B and C.
It is assumed there is no error in the detection of the spins or the
transmission of the hidden variables.  As the variables are independent,
and it is well known from observation of single particles that the spin
probability of clockwise spin being observed in any axis is 0.5, we see
that there are exactly 8 equally probable combinations, possibilities
denoted 1 - 8 in column i.

Bell suggested that sender Alice and receiver Bob, for each particle pair,
select a column at random and observe the spin.  That's all there is to the
experiment.

To see the expected results, look at Table 2.

a b matches
- - -------
A D 8/8
A E 4/8
A F 4/8
B D 4/8
B E 8/8
B F 4/8
C D 4/8
C E 4/8
C F 8/8

Table 2 - Expected results


In Table 2 column a indicates the axis Alice chooses to observe.  Column b
indicates the axis Bob chooses to observe at the same time.  We can
determine the probability of a match by comparing the two columns of
equally probable outcomes shown in table in Table 1.  By "match" here we
mean the observation of opposed, i.e. conjugate, spins.  For example, the
first row of Table 2 has the entries, A, D, and 8/8.  This means that when
Alice chooses axis A, and Bob coincidentally also chooses axis A, i.e
column D, then both will always observe complimentary spins.  We get 8 out
of 8 matches.  This is the principle of, the definition of in this case,
entanglement. When we look at row 2 of Table 2, we have the entries A, E,
4/8.  This is because there are only 4 possible ways out of 8 outcomes,
each equally probable, that a match occurs.  Summing up the entries in
Table 2, we see that there are 9*8 = 72 possible outcomes to the
observation of a single entangled pair, and there 3*(8+4+4) = 48 possible
matches.  There is thus a 2/3 probability of a match for a given particle
pair.

That is all there is to it!  If there are hidden variables, then there will
be a 2/3 probability of a match.

The Aspect experiment actually yields a 1/2 probability of a match.  It was
deduced from this there is no hidden variable involved.

This is quite amazing.  If the (thought) experiment data for 7200 trials is
tabulated in the format of Table 2, we might expect it to look something
like the idealization shown in Table 3.


a b matches
- - -------
A D 800/800
A E 200/800
A F 200/800  Total matches 3600
B D 200/800  Total trials 7200
B E 800/800  Match probability 0.5
B F 200/800
C D 200/800
C E 200/800
C F 800/800

Table 3 - Idealized experimental results


The amazing thing that has happened is a reduction of the probability of a
match when Alice and Bob have chosen differing axes to observe.  We know
they get a match 100 percent of the time when choosing the same axes, i.e
in the combinations A D, B E, and C F.  The matches in the differing axes
have in effect been "discorrelated", to coin a term, reduced in matching by
50 percent from what they should be if programmed by hidden variables.  The
computer programs inside the particle pairs appear to have no means to
accomplish this discorrelation without knowing what choice of axis was made
by both Alice and Bob.  Since Alice and Bob can chose the axis to observe
the last moment, it appears the computer programs would have to communicate
faster than light to do their work.

However, perhaps Table 1 can be modified to restrict possible combinations.
After all, the spin of one particle can not be measured in all three axes
at once.  It may be that spin direction in orthogonal axes are not
independent variables.  Suppose, for example, that spin in all three axes
can not be the same at one time.  We then have Table 4.


i A B C D E F

2 0 0 1 1 1 0
3 0 1 0 1 0 1    i - possible combination (row) number
4 0 1 1 1 0 0    A, B, C - Alice's possible observations
5 1 0 0 0 1 1    D, E, F - Bob's corresponding observations
6 1 0 1 0 1 0
7 1 1 0 0 0 1

Table 4 - Hidden variable table prior to weighting considerations

Tabulation of Table 4 still shows Bell's inequality to be in effect.  The
expected percent of total matches exceeds 50 percent.  However, suppose we
now simply decide to weight each row's probability.  This results in Table
5.


w A B C D E F

g 0 0 0 1 1 1    Key:
h 0 0 1 1 1 0
i 0 1 0 1 0 1    w - weight for given row
j 0 1 1 1 0 0    A, B, C - Alice's possible observations
k 1 0 0 0 1 1    D, E, F - Bob's corresponding observations
m 1 0 1 0 1 0
n 1 1 0 0 0 1    Let T = (g+h+i+j+k+m+n+p)
p 1 1 1 0 0 0

Table 5 - Prospective hidden variable table for observations by Alice and Bob


Table 6, below, is a tabulation of the entries in Table 5.


a b matches
- - -------
A D T/T
A E (g+h+n+p)/T
A F (g+i+m+p)/T
B D (g+h+n+p))/T       Total possibilities = 9*T
B E T/T                Total matches = 3*T + 6*g + 6*p + 2*(h+i+j+k+m+n)
B F (g+j+k+p)/T        Match probability desired .5
C D (g+i+m+p)/T
C E (g+j+k+p)/T
C F T/T

Table 6 - Expected results based on Table 5

Here again the term "match" refers to spin orientations being conjugate,
i.e. 1 and 0 or 0 and 1 in the columns chosen in Table 5.

We can immediately see the justification for throwing out rows 1 and 8, as
their weights g and p have factors of 9.  We thus set g=p=0, which throws
out rows 1 and 8.

Further, even with g=p=0, to obtain the desired probabilities of 1/4 for
the case where differing axes are chosen, we obtain from Figure 6 the
following equations:

   (h + n)/T = 1/4
   (i + m)/T = 1/4
   (j + k)/T = 1/4

which says:

   4h + 4n = T
   4i + 4m = T
   4j + 4k = T

and adding all the above:

   4(h+i+j+k+m+n) = 3T
   4T = 3T
   T=0

so the weights all disappear in a flash!  This in itself is sufficient to
prove the impossibility of hidden variables.

Bell's inequality, however, rests on the overall observed hits.  We have
from Table 5 that T = h+i+j+k+m+n and from Table 6 that total possibilities
= 9*T.  Total matches from Table 6 is 3*T + 2*T = 5*T.  We want
(matches)/(possibilities) = 0.5.  However, the ratio
(matches)/(possibilities) = (5*T)/(9*T) = 5/9, no matter what we chose for
the weights.  If g and/or p are non zero the ratio is worse than 5/9.
Bell's inequality thus holds no matter how the 8 possible spin combinations
are weighted.

Regards,

Horace Heffner          


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