I wrote earlier:
>
> For an electron-positron-electron "group" with a loop circumference of 2(pi)* 2.82 e-15 meters
> at 4.9e-11 ampere meters the current ( I ) = 4.8e-11/1.765e-14 = 2.72e3 amperes in each loop.
>
Going by this approach, the "Strong Force" between the disks or loops at a separation distance (d) is:
1.0e-7 * 4.8e-11^2/d^2 newtons, keeping in mind that the magnetic force is length dependent the
force between the electron-positron-electron if their separation d is comparable to their radius r,
2.304e-28/(2.82e-15)^2 = 28.97 newtons or about 65 pounds.
By the same token the strong force between the three quarks in a proton with separation
distance d comparable to a disk or loop radius of 2.35e-18 meters:
2.304e-28/(2.35e-18)^2 = 4.17e7 newtons or almost 10 million pounds. A "glue" force to reckon with when you
attempt to break it with high energy particles.
The High Energy Physics "Tailors" have woven quite a wardrobe for the Emperor.
Frederick
