Looks like you guys can believe most any number of things before breakfast!
At 8:09 AM 12/13/4, Frederick Sparber wrote: >Something to mull over, Jones. > >http://www.conformity.com/0102reflections.html > >"The dual to the Hertzian dipole is our fourth case, a sinusoidally >excited current loop. A current loop is characterized by its "moment," >which is the product of the current it carries times its amplitude. >Looking at figure 2, we see that the electric and magnetic fields for a >sinusoidally driven infinitesimal current loop mirror those for the >Hertzian dipole. Here, the near field magnetic field exhibits 1/r3 >behavior, while the near-field electric strength falls off as 1/r2. In the >far field, both E and H exhibit 1/r behavior. Their ratio, which is the >wave impedance, is the characteristic impedance of the surrounding medium, >just as it is for the Hertzian dipole. " > >Force at far = 1/r^2 ?? Actually it says 1/r behavior at far field. It is repeated other places, so it doesn't look like a typo. Fig. 3 shows far field in this case to begin at r/lambda = 5 to 10. At 8:14 AM 12/13/4, Jones Beene wrote: >EXCELLENT, Fred. This is all starting to fit together like a >jigsaw puzzle. I had a hunch we would find power laws in >there somewhere. You need look no further if the force and thus available energy that can be obtained from the oscillating source is 1/r in nature. For example, you could place a 10 GHz dipole in the center of a 3 meter radius sphere. Lambda = c/nu = 3 cm. Far field by the definition thus begins at 10 lambda = 30 cm. Suppose the total radiation from the dipole measured at a spherical surface of 30 cm radius were P=10 watts. At 3 meters radius we would expect the power density to be reduced by a factor of 1/10 over that produced at 30 cm, but the area is 100 times as large, so we get 10 times the power, or 100 watts. All you have to do is cover the surface of the 3 m diameter sphere with 3 cm antennae connected to rectifiers and you have a COP of 10, less deductions for rectification efficiency, etc. If you want a space drive just remove half the outer sphere, and replace it with a 30 cm radius reflector that reflects the radiation beck to the 3 m radius hemisphere. Since the pressure exerted on the outer 3 m sphere is 10 times that exerted on the 30 cm reflector, you have an inertial space drive. All pretty darn handy, free energy plus a warp drive all at the same time! Regards, Horace Heffner
