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Fred ,
Below is a reply from Eric Lerner inregard to your post below
>Hi Richard,
The electrostatic repulsive force (coulomb barrier) between
a proton (Z =1) and the boron nucleus (Z = 5 ) at an approach
distance d, is 1 * 5 * kq^2/d^2 = 1,152 newtons (258 pounds) at
d = 1.0e-15 meters or 0.00115 newtons at d = 1.0e-12 meters.
3/5th of that for the Proton 7 Lithium barrier, 2/5th for Deuterium
-3 Helium
and 1/5th for the D-D or D-T coulomb barrier,
Quite a hill to climb. Cockcroft and Walton bombarded boron
with
500 KeV protons in 1926 and got miniscule quantities of fusion
reactions.
Wish them luck with their "Billion Degree" (100 KeV) Focus Fusion
device
where the protons and the boron nuclei are all going in the same
direction. :-)
Fred
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- Re: Focus Fusion RC Macaulay
- Re: Focus Fusion Frederick Sparber
- Re: Focus Fusion RC Macaulay
- Re: Focus Fusion Frederick Sparber
- Re: Focus Fusion Jones Beene
- Re: Focus Fusion RC Macaulay
- Re: Focus Fusion Robin van Spaandonk
- Re: Focus Fusion Frederick Sparber

