http://www.wolframalpha.com/input/?i=energy+to+heat+1.2+kg+of+water+to+100+celsius
Wow, wolfram is amazing. Who needs to be a scientist! :D On Sun, Dec 28, 2014 at 2:58 PM, Blaze Spinnaker <blazespinna...@gmail.com> wrote: > errr, 4.8 joules in a calorie even. Yeah science ain't my strong suit! > I should just stick to the social proof thing.. > > On Sun, Dec 28, 2014 at 2:57 PM, Blaze Spinnaker <blazespinna...@gmail.com > > wrote: > >> sorry, 4.8 calories in a joule. Nvm >> >> On Sun, Dec 28, 2014 at 2:51 PM, Blaze Spinnaker < >> blazespinna...@gmail.com> wrote: >> >>> If it takes 540 calories are needed to turn 1 gram (at 100 degrees >>> Celsius) of water to steam, than that's 540 * 1200 * .23 = 149000 joules, >>> right? >>> >>> On Sun, Dec 28, 2014 at 2:45 PM, Blaze Spinnaker < >>> blazespinna...@gmail.com> wrote: >>> >>>> Also... is 2712000 the right amount for vaporization of the water? >>>> Doesn't it have to be dry steam to reach that energy amount? Looking at his >>>> set up, it seems like it would be pretty wet. >>>> >>>> On Sun, Dec 28, 2014 at 2:26 PM, Blaze Spinnaker < >>>> blazespinna...@gmail.com> wrote: >>>> >>>>> >>>>> https://docs.google.com/document/d/1Y3Bxr_aE2iosEKpGFUZiQgAcuT8AFN78RFCAlR-JqNw/edit >>>>> >>>>> On Sun, Dec 28, 2014 at 2:26 PM, Blaze Spinnaker < >>>>> blazespinna...@gmail.com> wrote: >>>>> >>>>>> Note by translator Stoyan Sarg: The initial heating power and >>>>>> temperature before reaching 10000C is not shown in the plot of slide >>>>>> #16 (does he mean 17?). Is it taken into account for the accumulated >>>>>> energy? If not a much longer test is needed for estimation of the COP. >>>>>> >>>>> >>>>> >>>> >>> >> >
