Robin--
You say that the LiHy4 item carries a negative charge. I assume you mean it
is an negative ion. How do you know this? Is the electronic configuration
you suggest 4 pairs of electrons, i.e., a total negative charge of 8 with a
positive charge of 7?
It seems such a ion would be di-polar and line up preferentially in an
electric field and or a magnetic field if it has a magnetic moment. A
di-polar property would allow it to get even closer to a positive local
nucleus. This reminds me of the theory of Gullstrom involving bound
neutron tunneling that was discussed on Vortex a month or so back.
Bob
----- Original Message -----
From: <mix...@bigpond.com>
To: <vortex-l@eskimo.com>
Sent: Monday, January 19, 2015 5:54 PM
Subject: Re: [Vo]:the "hole" truth and nothing but
In reply to Jones Beene's message of Sun, 18 Jan 2015 09:38:26 -0800:
Hi,
[snip]
The mass-energy of the displacement hole for lithium++ is measured at ~81
eV, which is a decent fit for the 3 x 27.2 = 81.6 eV (which is the exact
Rydberg multiple). In short, lithium is better than a 99% fit as a Mills
catalyst. But BLP has not been able to pull off this kind of simple robust
experiment with lithium - despite the two decade head start.
When LiAlH4 decomposes, the H- gives it's excess electron back to the
metals.
That results in the formation of a Li atom and H atoms essentially from the
same
molecule, i.e. in close proximity. This is the ideal condition for catalysis
of
the shrinkage reaction.
I pointed this out to Mills years ago (with regard to the thermal
decomposition
of KH).
Furthermore, the "m" of Li is 3 (as Jones pointed out) which facilitates a
shrinkage from p=1 (i.e. the ground state) directly to p=4, implying that
there
should be lots of H[n=1/4] formed.
The binding energy (proper usage) of LiHy4- (i.e. a tetrahedron comprising 4
H[n=1/4]- ions and a central Li3+ nucleus) is -193 eV, so there is a strong
"incentive" for this object to form.
(See http://rvanspaa.freehostia.com/LiHy4-.pdf)
Once formed, it carries an excess negative charge, and hence is attracted to
other nuclei, facilitating nuclear reactions, because of it's small size,
which
allows it to get closer than normal to said nuclei.
Regards,
Robin van Spaandonk
http://rvanspaa.freehostia.com/project.html
